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If two isosceles triangles have a common base,prove that the line joining their vertices bisects them at right angles. |
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Answer» Too prove=AD bisects BBC at right angles Proof=2N `/_ABC ans /_ADC` AB=AC(given) BD=CD(given) BC=BC(common) `/_ABC cong /_ADC(S S S)` `/_1=/_2` `In /_ABE and /_ACE` AB=AC `/_a=/_2` AE=AE(common) `/_ABE cong /_ACE(SAS)` BE=CE `/_3=/_4` `/_3+/_4=180^@` `2/_3=180^@` `/_3=90^@`. |
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