1.

If two of the zeros of the polynomial f(x)=x^3+(6-√3)x^2+(-1-√3)x+30-6√3 are 3 and -2 then, the other zero will be ____________(a) -√3(b) 5(c) 5-√3(d) 5+√3This question was posed to me by my school principal while I was bunking the class.Asked question is from Division of Polynomial in portion Polynomials of Mathematics – Class 10

Answer»

Correct choice is (C) 5-√3

To explain I WOULD SAY: SINCE the zeros of the polynomial are 3 and -2.

The divisor of the polynomial will be (x-3) and (x+2).

Multiplying (x-3) and (x+2) = x^2+2x-3x-6=x^2-x+6

Dividing, x^3+(6-√3)x^2+(-1-√3)x+30-6√3 by x^2-x+6

We get, x-5+√3 as quotient.

Hence, the third zero will be 5-√3.



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