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If two slits in `YDSE` have width ratio `4 : 1`, deduce the ratio of maxima and minima in the interference pattern. |
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Answer» Here, `(w_(1))/(w_(2)) = (4)/(1) = (a^(2))/(b^(2))` `:. (a)/(b) = (2)/(1)` `(I_(max))/(I_(min)) = (a + b)^(2)/(a - b)^(2) = (2b + b)^(2)/(2b - b)^(2) = (9)/(1)` |
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