Saved Bookmarks
| 1. |
If two zeroes of the polynomial f(x)=x^2-4x^2-3x +12 find third term |
| Answer» Let ,\xa0{tex}\\alpha,\\beta,\\gamma {/tex}\xa0be the zeroes of the polynomial where,{tex}\\alpha = \\sqrt { 3 } , \\beta = - \\sqrt { 3 }{/tex}{tex} \\alpha + \\beta + \\gamma = - \\frac { \\text { Coeff. of } x ^ { 2 } } { \\text { Coeff. of } x ^ { 3 } } {/tex}{tex}\\alpha + \\beta + \\gamma = - \\left( \\frac { - 4 } { 1 } \\right){/tex}.{tex}\\Rightarrow \\quad \\sqrt { 3 } - \\sqrt { 3 } + \\gamma = 4{/tex}{tex}\\Rightarrow \\quad \\gamma = 4{/tex}Hence, third zero is 4. | |