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If `|{:(x+1, x-1), (x-3, x+2):}| = |{:(4, -1), (1, 3):}|`, find the value of x. |
Answer» We have `|{:(x+1, x-1), (x-3, x+2):}| = |{:(4, -1), (1, 3):}|` `hArr (x+1) (x+2)-(x-3)(x-1) = (4 xx 3)-1 xx (-1)` `hArr (x^(2) +3x +2) -(x^(2) -4x +3) = 12+1` `hArr 7x -1 = 13 hArr 7x = 14 hArr x =2` Hence, x =2. |
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