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If x=2/3 and x=-3 are the roots of the equation ax2+7x+b=0, find the values of a and b

Answer» X=2/3. X=-33x-2=0. X+3=0(3x-2)(x+3)3x2+9x-2x-63x2+7x-6So as we can see that on comparing both equation we get that A=3B=-6


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