If x=2 and x=3 are roots of equation (3x)2 - 2kx +2km= 0, find the val

1.	If x=2 and x=3 are roots of equation (3x)2 - 2kx +2km= 0, find the value of k, m
Answer» It is given that x = 2 and x = 3 are roots of the equation 3x2 - 2kx + 2m = 0.{tex}\\therefore{/tex} 3 {tex}\\times{/tex}\xa022 - 2k {tex}\\times{/tex}\xa02 + 2m = 0 and 3 {tex}\\times{/tex}\xa032 - 2k {tex}\\times{/tex}\xa03 + 2m = 0{tex}\\Rightarrow{/tex}\xa012 - 4k\xa0+ 2m = 0 and 27 - 6k\xa0+ 2m = 0{tex}\\Rightarrow{/tex}\xa012 = 4k\xa0- 2m...(i) and 27 = 6k - 2m...(ii)Solving i and ii equation, we get k =\xa0{tex}\\frac { 15 } { 2 }{/tex}\xa0and m = 9

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