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If X=2 and X=3 are roots of the equation 3x² -2kx +2m=0 find the value of k and m

Answer» Sum of roots = -( coeff.of x)/coeff.of x^22+3 = -(-2k)/35 = 2k/32k = 15k = 15/2Product of roots = constant term/ coeff.of x^22×3 = 2m/36 = 2m/3m = 6 × 3/2 = 9


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