If x=2 & x=3 are the roots of the equation 3x2-2mx+2n=0 then find the value of m and n

If x=2 & x=3 are the roots of the equation 3x2-2mx+2n=0 then find the

1.	If x=2 & x=3 are the roots of the equation 3x2-2mx+2n=0 then find the value of m and n
Answer» 3x2 - 2mx + 2n = 0x = 22 (2)2 - 2m(2) + 2n = 02(4) - 4m +2n = 08 - 4m + 2n = 04- 2m + n = 02m - n = 4.... (i)x = 32 (3)2 - 2m(3) + 2n = 02(9) - 6m +2n = 018 - 6m + 2n = 03m - n = 9 ...... (ii)After solving m = 5 and n = 6.\xa0 M=15/2N=9