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If x=3 is one root of the q.e x^-2kx-6=0 then find k

Answer» Put x=3 in eq x"-2kx-6=0 (3)"-2k (3)-6=0 9-6k-6=0 9-6-6k=0 3-6k=0 3=6k K=3/6 K=1/2


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