InterviewSolution
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InterviewSolution
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If x=3 is one root of the quadratic eq x2-2kx-6=0 |
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Answer» x2-2kx-6=0(3)square-6k-69-6k-6=03-6k=0-6k=-3k=-3/-6k =1/2 (x)2 -2kx -6=0,(3)2-2k(3)-6=09-6k-6=03-6k=0So, k=1/2 k = 1/2 sorry wrong solution added.Correct solution isx2 - 2kx - 6 = 0x = 3(3)2 - 2k(3) - 6 = 09 - 6k - 6 = 0- 6k + 3 = 06k = 3k = 3/6k = 1/3 x2 - 2kx - 6 = 0x = 3(3)2 - 2k(3) - 6 = 09 - 6k - 6 = 02 - 6k = 06k = 2k = 2/6k = 1/3 Let p(x)=x^2-2kx-6Let X = 3 in p(x)p(3)=(3)^2 - 2k(3) -6 =9-6k-6 =3-6k -3=-6k 3=6k 3/6=k 1/2=k Value of k=6 |
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