If x=3 is one root of the quadratic equations x2-2kx-6=0 then find the

1.	If x=3 is one root of the quadratic equations x2-2kx-6=0 then find the value of k.
Answer» p(x)=x²-2kx-6=0, p(3)=3²-2×k×3-6=0, =9-6k-6=0, =3-6k=0, =6k=3, =k=3/6, =k=½Therefore, the value of k is ½. K=1/2 The equation is x square - 2kx - 6

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