InterviewSolution
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InterviewSolution
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If [(x + a)/a] + [(x + b)/b] + [(x + c)/c] = 3, and x ≥ 1 then find the value of (ab + bc + ca)?1. 22. 03. 14. 3 |
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Answer» Correct Answer - Option 2 : 0 Given: [(x + a)/a] + [(x + b)/b] + [(x + c)/c] = 3 Calculation: ∵ [(x + a)/a] + [(x + b)/b] + [(x + c)/c] = 3 ⇒ x/a + a/a + x/b + b/b + x/c + c/c = 3 ⇒ x/a + 1 + x/b + 1 + x/c + 1 = 3 ⇒ x/a + x/b + x/c + 3 = 3 ⇒ (bcx + acx + abx)/abc = 3 – 3 ⇒ (bcx + acx + abx)/abc = 0 ⇒ [x(ab + bc + ca)]/abc = 0 As from the question x ≥ 0 ∴ (ab + bc + ca) = 0 |
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