If (x+a) is a factor of 2x^2+2ax+5x+10 then find a

1.	If (x+a) is a factor of 2x^2+2ax+5x+10 then find a
Answer» p(x) = 2x²+2ax+5x+10 ............(i),....................take, x+a = 0 =› x = -asince x+a is a factor of (i) .............................therefore, .........................................................p(-a) = 0 ............................................................=› 2(-a)² + 2a(-a)+5(-a)+10 = 0 ......................=› 2a² - 2a² - 5a + 10 = 0 .................................=› -5a = -10 =› a = 2

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