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If x=a sin theta , y= b cos theta then determine the value of b^2 x^2+a^2 y^2 |
| Answer» x/a=sin theta and y/b= cos theta.. Now after squaring both sides we get x^2/a^2= sin^2 theta and y^2/b^2= cos^2. Now add both the equations. Then you\'ll get the value of b^2 x^2+ a^2 y^2 as sin^2 theta+cos^2 theta which is 1 | |