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If `x=at^2` and y=2 at then find `dy/dx` |
Answer» `x=at^2` `rArr dy/dx =a.d/dt(t^2)=a.2t=2at` and y=2 at `rArr dy/dx =2a.d/dt (t)=2a .(1)=2a` Now `dy/dx=(dy//dt)/(dx//dt)=(2a)/(2 at) =1/t.` |
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