

InterviewSolution
Saved Bookmarks
1. |
If `x , y in R ,`then the determinant `=|cosx-sinx1sinxcosx1cos(x+y)-sin(x+y)0|`lies in the interval`[-sqrt(2),sqrt(2)]`(b) `[-1,1]``[-sqrt(2),1]`(d) `[-1,-sqrt(2)]` |
Answer» `|(cos x , -sin x,1),(sin x, cos x,1),(cos(x+y), -sin(x+y), 0)|` `|(cos x, -sin x,1),(sin x, cos x,1),(cos x cos y - sin xsiny , -sinxcosy - cosx siny , 0)|` `r_3 -> r_3 - cosy(r_1) + siny(r_2)` `|(cosx, - sinx,1),(sin x, cos x,1),(0,0, siny - cosy)|` `(sin y - cos y)[cos^2 x - (-sin^2x)]` `= (siny - cos y)(cos^2x+sin^2 x)` `= siny - cosy` `= -[cosy - siny]` `= - sqrt2[ 1/sqrt2 cos y - 1/sqrt2 sin y]` `- sqrt2 sin(pi/4 - y)` when it is `=1` `/_= - sqrt2` when it is `= -1` `/_ = sqrt2` a is correct option |
|