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If x,y,z are in a.p.then what is the value of (x+y-z) (y+z-x).. |
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Answer» Ohhh. x, y and z are in the AP.So, 2y = x + zx = 2y - z .......(1) (x + y - z)(y + z - x) .......(2)Substituting (1) in (2)[(2y - z) + y - z][y + z - (2y - z)]= (2y - z + y - z)(y + z - 2y + z)= (3y - 2z)(2z - y)= 6yz - 3y2 - 4z2 + 2yz= 8yx - 3y2 - 4z2 I HOPE YOU GOT IT!!!!!!!!!!!!!!!!!!! I have asked question. Yes |
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