1.

If x2 - 6x + 1 = 0, then the value of \({x^2} + \frac{1}{{{x^2}}}\) is1. 302. 343. 324. None of the above

Answer» Correct Answer - Option 2 : 34

Calculation

x2 - 6x + 1 = 0

Dividing the whole equation by x,

x - 6 + 1/x = 0

\(\Rightarrow x + {1 \over x} = 6\)

Squaring both sides we get,

\(x^2 + {1\over x^2} + 2 = 36\)

\(\Rightarrow x^2 + {1\over x^2} = 36 - 2 = 34\)



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