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If x2 - 6x + 1 = 0, then the value of \({x^2} + \frac{1}{{{x^2}}}\) is1. 302. 343. 324. None of the above |
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Answer» Correct Answer - Option 2 : 34 Calculation x2 - 6x + 1 = 0 Dividing the whole equation by x, x - 6 + 1/x = 0 \(\Rightarrow x + {1 \over x} = 6\) Squaring both sides we get, \(x^2 + {1\over x^2} + 2 = 36\) \(\Rightarrow x^2 + {1\over x^2} = 36 - 2 = 34\) |
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