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If x4 + x2y2 + y4 = 63, and x2 + xy + y2 = 7, then find the value of (x/y + y/x) ?1. -42. 83. -84. 4 |
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Answer» Correct Answer - Option 3 : -8 Calculation: As we know that, x4 + x2y2 + y4 = (x2 - xy +y2) (x2 + xy + y2) According to the question x4 + x2y2 + y4 = 63, and x2 + xy + y2 = 7 . . . (1) ⇒ 63 = (x2 - xy +y2) × 7 ⇒ (x2 - xy +y2) = 9 . . . (2) Add equation (1) and (2) ⇒ 2(x2 + y2) = 16 ⇒ x2 + y2 = 8 The value of (x2 + y2) put in equation (1) ⇒ xy = 7 - 8 = -1 Now, ⇒ (x/y + y/x) ⇒ (x2 + y2)/xy ⇒ 8/-1 ⇒ -8 ∴ The required value is -8. |
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