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If `y=cos^(-1)x`, find `(d^2y)/(dx^2)`in terms of `y`alone. |
Answer» `y="cos"^(-1)x impliesx=cos y` `implies(dy)/(dx)= -sin y` `implies(dy)/(dx)= -(1)/("sin"y)= -"cosec " y` `implies (d^(2)y)/(dx^(2))=(d)/(dx)(-"cosec " y)` `="cosec "y" cot "y*(dy)/(dx)` `="cosec "y" cot"y(-"cosec "y)` `= -"cosec"^(2)y" cot "y` |
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