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If ` y = tan ^-1[x/(1+sqrt(1-x^2))] "then find" dy/dx` |
Answer» Let `x=sin theta` ` therefore y=tan ^-1[(sin theta)/(1+sqrt(1-sintheta))]` `=tan^-1[(sin theta)/(1+cos theta)]=tan ^-1[(2sin ""theta/2cos ""theta/2)/(2cos^2""theta/2)]` `tan^-1(tan""theta/2)=theta/2=1/2sin^-1x` `rArr dy/dx=1/2d/dxsin^-1x=1/(2sqrt(1-x^2))` |
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