InterviewSolution
y = (tan-1 x)2⇒ y1 = 2(tan-1 x) \(\frac{1}{1+x^2}\)⇒ (1 + x2)y1 = 2(tan-1 x)⇒ (1 + x2)y2 + y12x = 2 \(\frac{1}{1+x^2}\)⇒ (1 + x2)2 y2 + x(1 + x2)y1 = 2.
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