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`" if " |{:(yz-x^(2),,zx-y^(2),,xy-z^(2)),(xz-y^(2),,xy-z^(2),,yz-x^(2)),(xy-z^(2),,yz-x^(2),,zx-y^(2)):}|=|{:(r^(2),,u^(2),,u^(2)),(u^(2),,r^(2),,u^(2)),(u^(2),,u^(2),,r^(2)):}|` thenA. `r^(2)=x+y+z`B. `r^(2) =x^(2) =y^(2) +z^(2)`C. `u^(2) =yz+zx+xy`D. `u^(2) =xyz` |
Answer» Correct Answer - B::C In the left - hand determinant each element is the cofactor of the elements of the determinant `|{:(x,,y,,z),(y,,z,,x),(z,,x,,y):}|=Delta " (says) "` hence `Delta^(2) = |{:(x,,y,,z),(y,,z,,x),(z,,x,,y):}||{:(x,,y,,z),(y,,z,,x),(z,,x,,y):}|` `=|{:(x^(2)+y^(2)+z^(2),,xy+yz+zx,,xz+yx+zy),(Sigmaxy,,Sigmax^(2),,Sigmaxy),(Sigmaxy,,Sigmaxy,,Sigmax^(2)):}|` `|{:(r^(2),,u^(2),,u^(2)),(u^(2),,r^(2),,u^(2)),(u^(2),,u^(2),,r^(2)):}|" "underset(xy+yz+zx=u^(2))("Where "x^(2)+y^(2)+z^(2)=r^(2))` |
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