1.

Ifp(E)=0.05,what is the probabilityof\'notE\'?

Answer» We know,P(E) + P( not E) = 1here, P(E) = 0.050.05 + P(not E) = 1P(not E) = 1 -0.05 = 0.95
It\'s p(E\') = 0.95
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