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IfThe sum of first n terms of an Ap is given by Sn=2n²+3n . Find the sixteenth term of the Ap

Answer» Let n=1 Then s1=2(1)(1)+3(1) = S1=5=a -----------(1)Let. n=2 S2=2(2)(2)+3(2) S2=14. ------------(2) S2-S1=a2 14-5=9 So. A2=9Then. D=4 a16=a+15d a16=65Answer is 65.
S1=2×1^2+3×1=5S2=2×2^2+3×2=14SimilarlyS1=a1S2=a2+a1a2=14-5=9d=9-5=4a16=a+15d=5+15×4=65


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