1.

In a 5 litre solution of water and HCl, content of HCl is 20%. In order to attain a desirable result, strong HCl is required. Hence, 10 litres of 100% pure HCl is added. What is the strength of HCl in the mixture now?1). 73%2). 73.33%3). 73.66%4). 80%

Answer»

TOTAL content = 5 litres

Content of HCl = 20% of 5 litres

⇒ 20/100 × 5 = 1 litre

After 10 litres of 100% HCl is added,

Total content = 5 + 10 = 15 litres

STRENGTH of HCl = HCl content/Total content × 100

⇒ (1 + 10) /15 × 100

⇒ 11/15 × 100 = 73.33%

∴ Strength of HCl = 73.33%


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