In a acute angled triangle abc if sin (a+b-c)=1/2 and cos (b+c-a)=1/root 2 find angles a b and c

In a acute angled triangle abc if sin (a+b-c)=1/2 and cos (b+c-a)=1/ro

1.	In a acute angled triangle abc if sin (a+b-c)=1/2 and cos (b+c-a)=1/root 2 find angles a b and c
Answer» Since sin 45 degree equal to 1 by 2 and Cos 60 degree equal to one by root 2 so show a + b + C is equal to 60 degree and a + b + c equal to 45 degree so adding Season 1 and 2 we get that a and c is cancelled out and we get the value of B and putting the value of the input the equations will get that all the values up a b and c