1.

In a ΔABC, 3∠A + 2∠B = 275° and 2∠B + 3∠C = 325°, value of ∠B is.1. 30°2. 60°3. 40°4. 50°

Answer» Correct Answer - Option 2 : 60°

Given:

3∠A + 2∠B = 275° and 2∠B + 3∠C = 325°

Calculations:

In ΔABC,

∠A + ∠B + ∠C = 180° (sum of all the angles of a Δ is 180°)

3∠A + 2∠B = 275°      ----(1)

2∠B + 3∠C = 325°      ----(2)

Adding eq. (1) and eq. (2)

3∠A + 2∠B + 2∠B + 3∠C = 275° + 325° 

⇒ 3∠A + 3∠B + 3∠C + ∠B = 600° 

⇒ 180° × 3 + ∠B = 600°

⇒ ∠B = 600° - 540°

⇒ ∠B = 60° 

∴ The value of ∠B is 60°.



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