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In a parallelogram one angle is 4/5 of adjacent angle.determine the angles of parallelogram |
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Answer» et the first angle be x and the second angle be y.Then x = 4y/55x = 4y\xa05x - 4y = 0 ......(1)Also x + y = 180° .......(2)Multiply eq (2) by 5Then 5x + 5y = 900° ......(3)(3) - (1) we get9y = 900°y = 100°Put this value in eq (2)x + 100° = 180°x = 180° - 100°x = 80°Therefore, the angles are 80°, 100°, 80°, 100° because in a parallelogram opposite angles are equal. Solution:Let one angle be\xa0Other angle =\xa0But sum of adjacent angles in a parallelogram is\xa0\xa0\xa0\xa0\xa0\xa0\xa0Hence the angles of the parallelogram are |
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