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In a particular enzyme-catalyzed reaction, Vmax = 0.2 mol/sec and Km = 6 mM. Assume the enzyme shows standard Michaelis-Menten kinetics. What is the rate of the reaction when [S] = 20 mM?(a) 0.155(b) 0.156(c) 0.153(d) 0.152I have been asked this question in semester exam.Asked question is from General Reaction Kinetics for Biological Systems topic in section Homogenous Reactions of Bioprocess Engineering

Answer» CORRECT OPTION is (C) 0.153

The explanation is: V = Vmax[S] / (KM + [S])

= 0.2×20 / (6+20)

= 0.153.


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