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In a quadrilateral ABCD, angleA + angleD =90°.prove that AC^2 +BD^2=AD^2 + BC^2

Answer» Q.In a quadrilateral ΔBCD, ∠A+ ∠D = 90°. Prove that AC2\xa0+ BD2\xa0= AD2\xa0+ BC2.\xa0Given Quadrilateral ΔBCD, in which ∠A+ ∠D = 90°To prove\xa0AC2\xa0+ BD2\xa0= AD2\xa0+ BC2Construct Produce AB and CD to meet at E.
\xa0
^ iska matlab to the power h
Iska matlab AC ki power 2 hota h
Ismain (^) this means??
Plz post clearly this one...


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