1.

In a trapezium ,diagonals AC and BD meet at O.prove that ∆AOB ~∆COD

Answer» In trapezium opp. sides are parallelTherefore,AB||CD In ?AOB and ?CODAngle AOB =Angle COD (VOA)Angle ABO=Angle OCD (Alt .int. angles)Therefore ?AOB ~?COD (AA Similarity)Hence proved


Discussion

No Comment Found