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In a triangle ABC angla a is 90 degree , side AB is 5m and side AC is 9m then find side BC ? |
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Answer» Root 106 we know that by phythagorar thm. we get,BC^2 = AC^2 + AB^2BC^2 = (9)^2 + (5)^2BC^2= 81 + 25BC^2 = 106BC = ROOT 106 AB=5m,AC=9mBy Pythagoras theorem, BC²=AB²+AC²=)BC=√5²+9²=)BC=√25+81=)BC=√106=)BC=10.3m |
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