In a triangle abc< c =3< b =2(

1.	In a triangle abc< c =3< b =2(
Answer» Let angle b be= x. So, angle c be 3x . angle a be x/2.A+B+c =180.X/2+x+3x = 180. X/2+4x=180.(do through out multiplication of 2 in eqn).X+8x=360. 9x=360. X =40.Putting the value of x in a and b and c.a= 40÷2=20. b = 40 . c= 40(3) = 120.

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