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| 1. |
In a triangle ABC right angled at b ab=3cm Determine |
| Answer» Steps of construction:\tDraw a line segment BC = 4 cm.\tAt B, construct MBC = 90°.\tCut-off BA = 3 cm from BM.\tJoin AC.\tThus, right-angled {tex}\\triangle{/tex}ABC is obtained.\tBelow BC, make an acute CBX.\tAlong BX, mark off 7 points R1, R2, R3, R4, R5, R6, R7\tsuch that BR1 = R1R2 = R2R3 = R3R4 = R4R5 = R5R6 = R6R7\tJoin R5C.\tFrom R7, draw R7C1\xa0{tex}\\|{/tex} R5C, meeting BC produced at C1.\tFrom C1, draw C1A1\xa0{tex}\\|{/tex} CA, meeting BA produced at A1.\tThen, {tex}\\triangle{/tex}A1BC1 is the required triangle similar to {tex}\\triangle{/tex}A1BC1 such that each side of ABC is\xa0{tex}\\frac{7}{5}{/tex} times\tthe corresponding side of {tex}\\triangle{/tex}ABC. | |