In ABC DE || parallel . If CD = 3, EC = 4 cm , BE = 6 CM ,then DA is equals to

In ABC DE || parallel . If CD = 3, EC = 4 cm , BE = 6 CM ,then DA is e

1.	In ABC DE \|\| parallel . If CD = 3, EC = 4 cm , BE = 6 CM ,then DA is equals to
Answer» Given\xa0:-\tIn triangle ABC, DE \|\| AB.\tCD = 3 cm.\tEC = 4 cm.\tBE = 6 cm.To Find\xa0:-\tDA = ?Solution\xa0:-we know that,When a line is drawn parallel to one side of a triangle to intersect the other two sides in distinct points, then the other two sides are divided in the same ratio.given that,DE \|\| AB .so,→ CD / DA = CE / EBputting values we get,→ 3 / DA = 4 / 6→ 3 / DA = 2 / 3→ 2DA = 3 * 3→ DA = 9 / 2→ DA =\xa04.5 cm.