In ∆ABC, right angled at B, AB=24cm, BC=7cm. DetermineSinA, cosA

1.	In ∆ABC, right angled at B, AB=24cm, BC=7cm. DetermineSinA, cosA
Answer» In right angle traingle ABCAngle B= 90°By PGT(paytha goras theorem) in ∆ABCAB=24cm , BC=7cm So, AC×AC=BC×BC+AB×AB= Ac×Ac= 24×24+7×7=Ac×Ac=576+49=Ac×Ac=625=Ac=√625=Ac=25 Now, sinA= p/h=7/25CosA= B/H=4/25

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