In acute angle triangle sin(A+B-C)=1÷2,cos(B+C-A)=1÷√2.Find A,B,C.

1.	In acute angle triangle sin(A+B-C)=1÷2,cos(B+C-A)=1÷√2.Find A,B,C.
Answer» Sin(A+B+C)= 1/2Thus, A+B+C=30°....(i)Cos(B+C-A)= 45°.... (ii)A+B+C=180° [sum of all angles of a triangle]...(iii)Now solve it

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