In an acute angled triangle ABC,if tan (A+B-C)=1 and sec (B+C-A)=2 ,find values of A,B,C

In an acute angled triangle ABC,if tan (A+B-C)=1 and sec (B+C-A)=2 ,fi

1.	In an acute angled triangle ABC,if tan (A+B-C)=1 and sec (B+C-A)=2 ,find values of A,B,C
Answer» Btw it\'s nice question? Not sure ? tan(a+b-c)=1a+b-c=45degreessimilarlrysec(b+c-a)=2b+c-a=60 degressa-c=45-b,a-c=-60+bcomparing both the equations:45-b=b-60b=52.5from the equation it is understood that cac=90a=180-(90+52.5)=37.5