In an AP if d=-2 n=5 and tn=0 then find the vlaue of A.

1.	In an AP if d=-2 n=5 and tn=0 then find the vlaue of A.
Answer» Given:d = -2, n = 5 and an = 0We know that , an = a + (n - 1) d{tex}0 = a + (n - 1) d{/tex}{tex}[ a_n = 0]{/tex}{tex}0 = a + ( 5 - 1 ) (-2){/tex}0 = a + 4 {tex}\\times{/tex}\xa0- 2{tex}0 = a - 8{/tex}0 + 8 = aa = 8Hence, the value of a is 8.

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