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In an ap if d,=4, n=3 an=10then a is |
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Answer» an=a+(n-1)d10=a+(3-1)410=a+2×410=a+810-8=a2=a By formula An=a+(n-1)dAn=10N=3D=4So by putting value in formula 10=a+(3-1)410=a+(2)410=a+8A=10-8A=10So the first term (a) is 10 an=a+(n-1)d10=a+(3-1)410=a+(2×4)10-8=aa=2 |
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