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| 1. |
In an Ap Pth Qth and Rth terms are respectively a, b, c. Prove that p(b-c)+q(c-a) +r(a-b) =0. |
| Answer» Ap=a=a+[p-1]d by using Aq=b=a+[q-1]d An=a+[n-1]dAr=c=a+[r-1]da=a+pd-d -1b=a+qd-d -2c=a+rd-d -3Substituting 1 2 3 in p[b-c]+q[c-a]+r | |