In an isosceles triangle ABC, if AB=BC and AB2=2AC2\xa0,then angle C w

1.	In an isosceles triangle ABC, if AB=BC and AB2=2AC2\xa0,then angle C will be???\xa0
Answer» Ans.Given: AC = BCABC is an Isosceles triangleAB2\xa0= 2 AC2To Find =\xa0{tex}\\angle C{/tex}Proof :\xa0As\xa0AB2\xa0= 2AC2=>\xa0AB2\xa0= AC2\xa0\xa0+ AC2=>\xa0\xa0AB2\xa0= AC2\xa0\xa0+ BC2 [Given AC = BC]So By Converse of Pythagoras theorem\xa0{tex}\\angle C = 90^o{/tex}\xa0

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