1.

In `DeltaP Q R ,`right-angled at Q (see figure), `P Q = 3 c m a n d P R = 6 c m`. Determine `/_Q P R`and `/_P R Q`

Answer» If we create a right angle triangle `Delta PQR` with given details,
then,
`sinR = PQ/PR = 3/6 = 1/2 =sin30^@=> R =30^@`
We know, `/_P+/_Q+/_R = 180^@`
`/_P+90+30 = 180=>/_P = 180-120=60^@`
So,`/_QPR = 60^@ and /_PRQ = 30^@`


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