In fig. PQ and PR are tangents to circle with centre O such that angle

1.	In fig. PQ and PR are tangents to circle with centre O such that angleQPR =50
Answer» In quad. PQOR,∠R+\xa0∠O+\xa0∠Q+\xa0∠P = 360∠P +\xa0∠O = 90∠O = 130Now,In ∆ROQ,∠RQO +\xa0∠QOR +\xa0∠ORQ = 180°Now as the sides OQ = RO because of radius of same circle... Hence.... OQR = 25°

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