Saved Bookmarks
| 1. |
In figure (1);(2) ,DE||BC find Ec in(1) and AD in (2) |
| Answer» In, ΔABCBC || DEIn ΔABC and ΔADE∠ABC = ∠ADE [corresponding angles]∠ACB = ∠AED [ corresponding angles]∠A = ∠A common⇒ ΔABC ~ ΔADEAD/DB = AE/EC1.5/3 = 1/ECEC = 3 × 1/1.5EC = 2 cm(ii) In ΔABC and ΔADE∠ABC = ∠ADE [corresponding angles]∠ACB = ∠AED [ corresponding angles]∠A = ∠A commonΔABC ∼ ΔADEAD/DB = AE/ECAD/7.2 = 1.8/5.4AD = (7.2 × 1.8)/5.4AD = 2.4 cm | |