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| 1. |
in figure DE parallel to BC then find value of x given AD=2cm DB=3cm DE=4cm and BC=x |
| Answer» Given That AD=2 cm , DB=3 cm DE= 4 cm BC=x{tex}\\begin{array}{l}As\\;DE\\parallel\\;BC\\\\So\\\\\\frac{AD}{AB}=\\frac{DE}{BC}\\\\\\frac2{2+3}=\\frac4x\\\\2x=4\\times5=20\\\\x=10\\\\\\end{array}{/tex}\xa0 | |