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In polynomial exercise 2.2 how 3x2-x_4=12x2 |
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Answer» The zeroes are 4/3 and -1.The relation between zeroes and coefficient are α+β=4/3+(-1)=-1/3=-(coefficient of x) /(coefficient of x^2)αβ=4/3*(-1)=-4/3=(constant term)/(coefficient of x^2). The zeroes are 4/3 and -1.Relation between zeroes and coefficient are α+β=4/3+(-1)=-(coefficient of x) / (coefficient of x^2)αβ=4/3*(-1)=(constant term) /coefficient of x^2) Puchna kya chahte ho bhai aap??? |
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