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इन समाकलनो का मान कीजिएः `int_(0)^(pi//4) tan^2xdx`

Answer» `underset(0)overset(pi//4)int tanx^(2)xdx`
`underset(0)overset(pi//4)int (sec^(2)x-1)dx=[tan x-x]_(0)^(pi//4)`
`=[tan ""(pi)/(4)-pi/4]-[tan 0-0]`
`=1-pi/4`


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