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इन समाकलनो का मान कीजिएः `int_(0)^(pi//4) tan^2xdx` |
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Answer» `underset(0)overset(pi//4)int tanx^(2)xdx` `underset(0)overset(pi//4)int (sec^(2)x-1)dx=[tan x-x]_(0)^(pi//4)` `=[tan ""(pi)/(4)-pi/4]-[tan 0-0]` `=1-pi/4` |
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